Answer
$16$
Work Step by Step
We know that for a matrix
\[
\left[\begin{array}{rr}
a & b \\
c &d \\
\end{array} \right]
\]
the determinant, $D=ad-bc.$
Hence here $D_1=xb-ya=8.$
We are looking for $D_2=2xb-2ya=2(xb-ya)=2(8)=16$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 8 - Review Exercises - Page 634: 32
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