College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 8 - Review Exercises - Page 634: 12

Answer

See below.

Work Step by Step

We know that \[ \left\{ \begin{array}{c} a_1x+b_1y+c_1z=d_1 \\ a_2x+b_2y+c_2z=d_2 \\ a_3x+b_3y+c_3=d_3 \\ \end{array} \right. \] becomes \[ \left[\begin{array}{rrr|r} a_1 & b_1 & c_1 & d_1 \\ a_2 & b_2 & c_2 & d_2 \\ a_3 & b_3 & c_3 & d_3 \\ \end{array} \right] \] Hence here the system of equations is: $\{x+2y+5z=-2,5x-3z=8,2x-y=0\}$
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