College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 8 - Review Exercises - Page 634: 14

Answer

$\begin{bmatrix} 6& 0 \\ 12& 24 \\ -6&12 \end{bmatrix}$

Work Step by Step

$6\begin{bmatrix} 1& 0 \\ 2& 4 \\ -1&2 \end{bmatrix}=\begin{bmatrix} 6\cdot1& 6\cdot0 \\ 6\cdot2& 6\cdot4 \\ 6\cdot-1&6\cdot2 \end{bmatrix}=\begin{bmatrix} 6& 0 \\ 12& 24 \\ -6&12 \end{bmatrix}$
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