College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 8 - Review Exercises - Page 634: 2

Answer

See below.

Work Step by Step

$x=0.5+3y$, thus $3(0.5+3y)-4y=4\\1.5+9y-4y=4\\5y=2.5\\y=0.5$ Thus $x=0.5+3(0.5)=2$
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