College Algebra (10th Edition)

Published by Pearson

Chapter 7 - Section 7.2 - The Parabola - 7.2 Assess Your Understanding - Page 515: 64

Answer

$\quad y^{2}=-(x-1)$

Work Step by Step

Opens $left$. By Table 2, $\begin{array}{|c|c|c|c|} \hline {focus}&{directrix}&{equation}& ... opens\\ \hline {(h-a,k)}&{x=h+a}&{(y-k)^{2}=-4a(x-h)} &left\\ \hline \end{array}$ Read from the graph: $\quad (h,k)=(1,0),$ so the equation has form $\quad y^{2}=-4a(x-1)$ Find $-4a$ by using the point on the graph (insert its coordinates into the equation) $1^{2}=-4a(0-1)$ $1=4a$ $-4a=-1$ The equation is $\quad y^{2}=-(x-1)$

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