Answer
$\quad (y-1)^{2}=-(x-2)$
Work Step by Step
Opens left. By Table 2,
$\begin{array}{|c|c|c|c|} \hline
{focus}&{directrix}&{equation}& ... opens\\ \hline
{(h-a,k)}&{x=h+a}&{(y-k)^{2}=-4a(x-h)} &left \\ \hline \end{array}$
Read from the graph: $\quad (h,k)=(2,1),$
so the equation has form $\quad (y-1)^{2}=-4a(x-2)$
Find $-4a$ by using the point on the graph (insert its coordinates into the equation)
$(0-1)^{2}=-4a(1-2)$
$1=4a$
$-4a=-1$
The equation is $\quad (y-1)^{2}=-(x-2)$
