College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 7 - Section 7.2 - The Parabola - 7.2 Assess Your Understanding - Page 515: 58

Answer

$\quad (x-1)^{2}=-(y-2)$

Work Step by Step

Opens down. By Table 2, $\begin{array}{|c|c|c|c|} \hline {focus}&{directrix}&{equation}& ... opens\\ \hline {(h,k-a)}&{y=k+a}&{(x-h)^{2}=-4a(y-k)}& down \\ \hline \end{array}$ Read from the graph: $\quad (h,k)=(1,2),$ so the equation has form $\quad (x-1)^{2}=-4a(y-2)$ Find $-4a$ by using the point on the graph (insert its coordinates into the equation) $(2-1)^{2}=-4a(1-2)$ $1=4a$ $-4a=-1$ The equation is $\quad (x-1)^{2}=-(y-2)$
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