Answer
$\quad x^{2}=4(y-1)$
Work Step by Step
Opens up. By Table 2,
$\begin{array}{|c|c|c|c|} \hline
{focus}&{directrix}&{equation}& ... opens\\ \hline
{(h,k+a)}&{y=k-a}&{(x-h)^{2}=4a(y-k)}&up\\ \\ \hline \end{array}$
Read from the graph: $\quad (h,k)=(0,1),$
so the equation has form $\quad x^{2}=4a(y-1)$
Find $4a$ by using the point on the graph (insert its coordinates into the equation)
$2^{2}=4a(2-1)$
$4=4a$
The equation is $\quad x^{2}=4(y-1)$
