Chapter 3 - Section 3.1 - Functions - 3.1 Assess Your Understanding - Page 212: 96

$B=-1$

We solve: $f(x)=\displaystyle \frac{2x-B}{3x+4}$ and $f(2)=\displaystyle \frac{1}{2}$ We solve for $B$: $f(2)=\frac{2*2-B}{3*2+4}$ $f(2)=\frac{4-B}{10}$ Since $f(2)=1/2$: $\frac{1}{2}=\frac{4-B}{10}$ $5=4-B$ $B=-1$