College Algebra (10th Edition)

$A=-4$
We are given: $f(x)=\displaystyle \frac{3x+8}{2x-A}$ and $f(0)=2$ We solve for $A$: $f(0)=\frac{3*0+8}{2*0-A}$ $f(0)=\frac{8}{-A}$ Since $f(0)=2$: $2=\frac{8}{-A}$ $-2A=8$ $A=-4$