College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Section 2.5 - Variation - 2.5 Assess Your Understanding - Page 193: 42

Answer

$k = 5$ New pressure P, when volume reduced to 80 litres = 19.375 atm

Work Step by Step

Volume V varies directly proportional with temperature T and inversely to pressure P $V = k\frac{T}{P}$ given V = 100 ltr, T=300K, and P = 15 atm => $100 = k\frac{300}{15}$ => k = 5 Now, To find P, when V becomes 80litres and T = 310K $80 = k\frac{310}{P}$ =>$P = \frac{5*310}{80} = 19.375\ atm$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.