College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Section 2.5 - Variation - 2.5 Assess Your Understanding - Page 193: 36

Answer

$\approx 54.86$ lb.

Work Step by Step

If the weight $w$ varies inversely with $d^{2}$, then there is a nonzero constant $k$ such that $w=\displaystyle \frac{k}{d^{2}}$ --- If $ w=55$ when $d=3960$, substituting, we find k: $55=\displaystyle \frac{k}{3960^{2}}\quad/\times 3960^{2}$ $k=862,488,000$ Thus, we write: $\displaystyle \quad w=\frac{862,488,000}{d^{2}}.$ If $d=3965$, $w=\displaystyle \frac{862,488,000}{3965^{2}}\approx 54.86$ lb.
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