College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Section 2.5 - Variation - 2.5 Assess Your Understanding - Page 193: 37

Answer

$V=\pi(r^{2}h).$

Work Step by Step

If $V$ varies jointly with $r^{2}$ and $h , $ there exists a nonzero number $k$ such that $V=k(r^{2}h).$ Given $k=\pi,$ we write $V=\pi(r^{2}h).$
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