College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Section 2.5 - Variation - 2.5 Assess Your Understanding - Page 193: 40



Work Step by Step

$F=kAv^2$, hence here $11=k\cdot20\cdot22^2$, thus $k=0.00113636363$ Hence if $A=47.125$ and $v=36.5$, then $F=0.00113636363\cdot47.125\cdot36.5^2\approx71.34$
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