College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Cumulative Review - Page 196: 7

Answer

$\color{blue}{x=\left\{1, 3\right\}}$

Work Step by Step

RECALL: $|x| =a \longrightarrow x = a \text{ or } x = -a$ Thus, using the rule above gives: $|x-2| = 1 \longrightarrow x-2=1 \text{ or } x-2=-1$ Solve each equation to obtain: $x-2=1 \\x=1+2 \\x=3$ or $x-2=-1 \\x=-1+2 \\x=1$ Therefore, the solutions are: $\color{blue}{x=\left\{1, 3\right\}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.