College Algebra (10th Edition)

Published by Pearson

Chapter 2 - Cumulative Review - Page 196: 5

Answer

no real solutions.

Work Step by Step

RECALL: A quadratic equation whose discriminant $b^2-4ac$ is negative has no real number solutions. The given quadratic equation has $a=1, b=2,$ and $c=5$. Solving for the discriminant gives: $b^2-4ac= 2^2-4(1)(5) = 4-20 = -16$ Since the discriminant is negative, the given equation has no real number solutions.

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