## College Algebra (10th Edition)

$\color{blue}{x = \left\{-3, 4\right\}}$
Factor the trinomial: $(x-4)(x+3)=0$ Equate each factor to $0$: $x-4 = 0 \text{ or } x+3=0$ Solve each equation above : $x-4 = 0 \\x-4+4=0+4 \\x=4$ or $x+3-3=0-3 \\x=-3$ Thus, the solutions are: $\color{blue}{x = \left\{-3, 4\right\}}$.