## College Algebra (10th Edition)

Published by Pearson

# Chapter 2 - Cumulative Review: 3

#### Answer

$\color{blue}{x = \left\{-\frac{1}{2}, 3\right\}}$

#### Work Step by Step

Factor the trinomial: $(2x+1)(x-3)=0$ Equate each factor to $0$: $2x+1 = 0 \text{ or } x-3=0$ Solve each equation above : $2x+1 = 0 \\2x+1-1=0-1 \\2x=-1 \\x =-\frac{1}{2}$ or $x-3+3=0+3 \\x=3$ Thus, the solutions are: $\color{blue}{x = \left\{-\frac{1}{2}, 3\right\}}$.

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