College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Cumulative Review - Page 196: 3


$\color{blue}{x = \left\{-\frac{1}{2}, 3\right\}}$

Work Step by Step

Factor the trinomial: $(2x+1)(x-3)=0$ Equate each factor to $0$: $2x+1 = 0 \text{ or } x-3=0$ Solve each equation above : $2x+1 = 0 \\2x+1-1=0-1 \\2x=-1 \\x =-\frac{1}{2}$ or $x-3+3=0+3 \\x=3$ Thus, the solutions are: $\color{blue}{x = \left\{-\frac{1}{2}, 3\right\}}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.