College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Section 10.3 - Probability - 10.3 Assess Your Understanding - Page 705: 30

Answer

See below.

Work Step by Step

Let $P(2)=P(4)=P(1)=P(3)=P(5)=x$. We also know that $P(2)+P(4)+P(1)+P(3)+P(5)=1$, thus $x+x+x+x+x=1\\5x=1\\x=0.2$. Thus $P(2)=P(4)=P(1)=P(3)=P(5)=0.2$.
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