College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Section 10.3 - Probability - 10.3 Assess Your Understanding - Page 705: 28

Answer

See below.

Work Step by Step

Let $P(H)=x$, then $P(T)=2x$. We also know that $P(T)+P(H)=1$, thus $2x+x=1\\3x=1\\x=\frac{1}{3}$. Thus $P(T)=\frac{2}{3},P(H)=\frac{1}{3}$.
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