College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Section 10.3 - Probability - 10.3 Assess Your Understanding - Page 705: 29


See below.

Work Step by Step

Let $P(2)=P(4)=P(6)=x$, then $P(1)=P(3)=P(5)=2x$. We also know that $P(2)+P(4)+P(6)+P(1)+P(3)+P(5)=1$, thus $x+x+x+2x+2x+2x=1\\9x=1\\x=\frac{1}{9}$. Thus $P(1)=P(3)=P(5)=\frac{2}{9},P(2)=P(4)=P(6)=\frac{1}{9}$.
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