## College Algebra (10th Edition)

Let $P(2)=P(4)=P(6)=x$, then $P(1)=P(3)=P(5)=2x$. We also know that $P(2)+P(4)+P(6)+P(1)+P(3)+P(5)=1$, thus $x+x+x+2x+2x+2x=1\\9x=1\\x=\frac{1}{9}$. Thus $P(1)=P(3)=P(5)=\frac{2}{9},P(2)=P(4)=P(6)=\frac{1}{9}$.