College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Section 10.3 - Probability - 10.3 Assess Your Understanding - Page 705: 15

Answer

3 Heads → $\frac{1}{8}$ 2 Heads and 1 Tail → $\frac{3}{8}$ 2 Tails and 1 Head → $\frac{3}{8}$ 3 Tails → $\frac{1}{8}$

Work Step by Step

The possible outcomes are: HHH, HHT, HTH, THH, HTT, THT, TTH, TTT Therefore the probability model can be 3 Heads → $\frac{1}{8}$ 2 Heads and 1 Tail → $\frac{3}{8}$ 2 Tails and 1 Head → $\frac{3}{8}$ 3 Tails → $\frac{1}{8}$
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