## College Algebra (10th Edition)

3 Heads → $\frac{1}{8}$ 2 Heads and 1 Tail → $\frac{3}{8}$ 2 Tails and 1 Head → $\frac{3}{8}$ 3 Tails → $\frac{1}{8}$
The possible outcomes are: HHH, HHT, HTH, THH, HTT, THT, TTH, TTT Therefore the probability model can be 3 Heads → $\frac{1}{8}$ 2 Heads and 1 Tail → $\frac{3}{8}$ 2 Tails and 1 Head → $\frac{3}{8}$ 3 Tails → $\frac{1}{8}$