Answer
25
Work Step by Step
Recall, $i=\sqrt{-1}$, so $i^{2}=-1$. Thus, we multiply by the conjugate to obtain:
$z*\overline{z}$
$=(3-4i)(\overline{3-4i})$
$=(3-4i)(3+4i)$
$=9+12i-12i-16i^{2}$
$=9-16*-1$
$=9+16$
$=25$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 1 - Section 1.3 - Complex Numbers; Quadratic Equations in the Complex Number System - 1.3 Assess Your Understanding - Page 112: 85
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