College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.3 - Complex Numbers; Quadratic Equations in the Complex Number System - 1.3 Assess Your Understanding: 57

Answer

$x=-4$ or $x=4$

Work Step by Step

We solve by factoring the difference of two squares: $x^{2}-16=0$ $x^{2}-4^2=0$ $(x+4)(x-4)=0$ $(x+4)=0$ or $(x-4)=0$ $x=-4$ or $x=4$
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