Answer
$x=-4$ or $x=4$
Work Step by Step
We solve by factoring the difference of two squares:
$x^{2}-16=0$
$x^{2}-4^2=0$
$(x+4)(x-4)=0$
$(x+4)=0$ or $(x-4)=0$
$x=-4$ or $x=4$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 1 - Section 1.3 - Complex Numbers; Quadratic Equations in the Complex Number System - 1.3 Assess Your Understanding - Page 112: 57
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