## College Algebra (10th Edition)

$3\pm i$
$x^{2}-6x+10=0$ We solve using the quadratic formula ($a=1,\ b=-6,\ c=10$): $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ $x=\frac{-(-6)\pm\sqrt{(-6)^{2}-4(1)(10)}}{2(1)}$ $x=\frac{-(-6)\pm\sqrt{36-40}}{2(1)}$ $x=\frac{+6\pm\sqrt{-4}}{2(1)}$ $x=\frac{6\pm 2i}{2}=3\pm i$ Recall, $i=\sqrt{-1}$