College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.3 - Complex Numbers; Quadratic Equations in the Complex Number System - 1.3 Assess Your Understanding - Page 112: 80


There are two identical real solutions.

Work Step by Step

$4x^{2}+12x+9=0$ To determine the nature of the solutions (without solving), we compute the sign of the discriminant in the quadratic formula ($a=4,\ b=12,\ c=9$): $b^{2}-4ac=12^{2}-4*4*9=144-144=0$ Since the discriminant is 0, there are two identical real solutions.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.