## College Algebra (10th Edition)

$4x^{2}+12x+9=0$ To determine the nature of the solutions (without solving), we compute the sign of the discriminant in the quadratic formula ($a=4,\ b=12,\ c=9$): $b^{2}-4ac=12^{2}-4*4*9=144-144=0$ Since the discriminant is 0, there are two identical real solutions.