College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.2 - Quadratic Equations - 1.2 Assess Your Understanding - Page 101: 32


The solution set is $\left\{-6, 6\right\}$.

Work Step by Step

Take the square root of both sides to obtain: $x = \pm \sqrt{36} \\x= \pm \sqrt{6^2} \\x = \pm 6$ Thus, the solution is $\left\{-6, 6\right\}$.
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