Answer
$\emptyset$
Work Step by Step
Distribute the parentheses
$x^{2}+4x+12=0$
Factor the LHS
For $x^{2}+bx+c$ we search for two factors of c, such that their sum is b...
For c=12, no two such factors exist (with a sum of 4).
The LHS can not be factored, and the equation has no real solutions.
Solution set: $\emptyset$
