College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.2 - Quadratic Equations - 1.2 Assess Your Understanding - Page 101: 29

Answer

$x=-\frac{3}{4}, 2$

Work Step by Step

We simplify as follows: $\frac{4(x-2)}{x-3}+\frac{3}{x}=\frac{-3}{x(x-3)}$ $\frac{4x(x-2)}{x(x-3)}+\frac{3(x-3)}{x(x-3)}=\frac{-3}{x(x-3)}$ $4x(x-2)+3(x-3)=-3$ $4x^{2}-5x-6=0$ $(4x+3)(x-2)=0$ $x=-\frac{3}{4}, 2$
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