College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.2 - Quadratic Equations - 1.2 Assess Your Understanding: 25


The solution set is {$-\frac{2}{3},\frac{3}{2}$}.

Work Step by Step

$6(p^2-1)=5p$ $6p^2-5p-6=0$ Distribute and write in standard form. $(2p-3)(3p+2)=0$ Factor. $2p-3=0$ or $3p+2=0$ Set each factor equal to $0$. $2p=3$ or $3p=-2$ Solve each equation. $p=\frac{3}{2}$ or $p=-\frac{2}{3}$ The solution set is {$-\frac{2}{3},\frac{3}{2}$}.
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