College Algebra (10th Edition)

The solution set is {$-\frac{2}{3},\frac{3}{2}$}.
$6(p^2-1)=5p$ $6p^2-5p-6=0$ Distribute and write in standard form. $(2p-3)(3p+2)=0$ Factor. $2p-3=0$ or $3p+2=0$ Set each factor equal to $0$. $2p=3$ or $3p=-2$ Solve each equation. $p=\frac{3}{2}$ or $p=-\frac{2}{3}$ The solution set is {$-\frac{2}{3},\frac{3}{2}$}.