## Algebra and Trigonometry 10th Edition

$\frac{-1}{(x-4+h)(x-4)}$
Let $y=x-4$. Then this is the same as exercise $61$, if we replace the $x$ with $y$. So the fraction is equal to $\frac{-1}{(y+h)y}=\frac{-1}{(x-4+h)(x-4)}$