## Algebra and Trigonometry 10th Edition

$\frac{x+1}{x-1}, x\ne0, x\ne1$
$\frac{x^2-1}{x}*\frac{x}{(x-1)^2}=\frac{(x-1)(x+1)}{x}*\frac{x}{(x-1)^2}=\frac{x+1}{x-1}$ (Cancel common factors from numerator and denominator)