## Algebra and Trigonometry 10th Edition

$\frac{2x-1}{2x}, x\ne0$
Canceling common terms and using exponent rules, we find: $\frac{\sqrt x-\frac{1}{2\sqrt x}}{\sqrt x}=\frac{\frac{2x-1}{2\sqrt x}}{\sqrt x}=\frac{2x-1}{2x}$