Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Prerequisites - P.5 - Rational Expressions - Exercises - Page 49: 53


$\frac{2x-1}{2x}, x\ne0$

Work Step by Step

Canceling common terms and using exponent rules, we find: $\frac{\sqrt x-\frac{1}{2\sqrt x}}{\sqrt x}=\frac{\frac{2x-1}{2\sqrt x}}{\sqrt x}=\frac{2x-1}{2x}$
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