## Algebra and Trigonometry 10th Edition

$tan~x~\rightarrow+\infty$ $cot~x~\rightarrow0^+$
As $x\rightarrow(\frac{\pi}{2})^-$, $sin~x\rightarrow1^-$ and $cos~x\rightarrow0^+$ Hence, as $x\rightarrow(\frac{\pi}{2})^-$: $tan~x\rightarrow\frac{1^-}{0^+}=+\infty$ $cot~x\rightarrow\frac{0^+}{1^-}=0^+$