Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 7 - 7.1 - Using Fundamental Identities - 7.1 Exercises - Page 514: 68


False. $tan~x=cot(\frac{\pi}{2}-x)$ It is also required to use a Pythagorean Identity.

Work Step by Step

$tan~x=cot(\frac{\pi}{2}-x)$ $tan^2x=cot^2(\frac{\pi}{2}-x)$ Use the Pythagorean Identity: $csc^2u=cot^2u+1$ $cot^2u=csc^2u-1$ $tan^2x=csc^2(\frac{\pi}{2}-x)-1$ $tan~x=\pm\sqrt {csc^2(\frac{\pi}{2}-x)-1}$
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