Answer
$\ln|cos~x|-\ln|sin~x|=\ln|cot~x|$
Work Step by Step
$\ln|cos~x|-\ln|sin~x|=\ln|\frac{cos~x}{sin~x}|=\ln|cot~x|$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.1 - Using Fundamental Identities - 7.1 Exercises - Page 514: 62
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