Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - 6.6 - Inverse Trigonometric Functions - 6.6 Exercises - Page 485: 99b


$0.125 $ and $0.253 $

Work Step by Step

We will take the sine of an angle. That is, $\sin \theta =\dfrac{5}{s}$ Now, take the inverse of the sine of an angle. $\theta=\arcsin (\dfrac{5}{s}) $ or, $\theta=\sin^{-1} (\dfrac{5}{s}) $ Plug in the data to obtain: $\theta=\arcsin (\dfrac{5}{40})=0.125 $ and $\theta=\arcsin (\dfrac{5}{20})=0.253 $
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