## Algebra and Trigonometry 10th Edition

$0.125$ and $0.253$
We will take the sine of an angle. That is, $\sin \theta =\dfrac{5}{s}$ Now, take the inverse of the sine of an angle. $\theta=\arcsin (\dfrac{5}{s})$ or, $\theta=\sin^{-1} (\dfrac{5}{s})$ Plug in the data to obtain: $\theta=\arcsin (\dfrac{5}{40})=0.125$ and $\theta=\arcsin (\dfrac{5}{20})=0.253$