There is an asymptote at $y=1$ and $y=-1$.
Work Step by Step
Both the functions are equal because $g(x)$ shows the equivalent algebraic expression of the function $f(x)$. We can see that there is an asymptote at $y=1$ and $y=-1$.
You can help us out by revising, improving and updating this answer.Update this answer
After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.