Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - 6.6 - Inverse Trigonometric Functions - 6.6 Exercises - Page 485: 70

Answer

$cot(arctan\frac{1}{x})=x$

Work Step by Step

Let $u=arctan\frac{1}{x}~~$ (Range: $-\frac{\pi}{2}\lt u\lt\frac{\pi}{2}$) Then: $\frac{1}{x}=tan~u$ $cot(arctan\frac{1}{x})=cot~u=\frac{1}{tan~u}=x$
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