## Algebra and Trigonometry 10th Edition

$y=160.86~ft$
Let the distance from the base of the tower to the guy (side adjacent to $θ$) be $y$: $tan~θ=\frac{opp}{adj}$ $tan~43°=\frac{150}{y}$ $y=\frac{150}{tan~43°}$ (Use a calculator to evaluate $tan~43°$) $y=160.86$