Answer
$d=6.572\text{ cm}$
Work Step by Step
Finding the thickness $t$ of the shaft at upper side: $$\tan 3^\circ=\frac{t}{15}$$ $$t=15\tan 3^\circ=0.786\text{ cm}$$
Then, the diameter will be:
$$d=5+2t=5+2(0.786)=6.572\text{ cm}$$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 6 - 6.2 - Right Triangle Trigonometry - 6.2 Exercises - Page 443: 68
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