Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - 6.2 - Right Triangle Trigonometry - 6.2 Exercises - Page 443: 69

Answer

$\sin 20^\circ=0.34$ $\cos 20^\circ = 0.94$ $\tan 20^\circ = 0.36$ $\cot 20^\circ = 2.75$ $\sec 20^\circ = 1.06$ $\csc 20^\circ = 2.92$

Work Step by Step

The point $(x,y)$ from our construction has the coordinates $(x,y)=(9.4,3.4)$, so we have: $x=9.4$ $y=3.4$ We calculate $\sin 20^\circ$: $\sin 20^\circ=\frac{y}{10}=\frac{3.4}{10}=0.34$ We calculate $\cos 20^\circ$: $\cos 20^\circ=\frac{x}{10}=\frac{9.4}{10}=0.94$ We calculate $\tan 20^\circ$: $\tan 20^\circ=\frac{y}{x}=\frac{3.4}{9.4}=0.36$ We calculate $\cot 20^\circ$: $\cot 20^\circ=\frac{x}{y}=\frac{9.4}{3.4}=2.75$ We calculate $\sec 20^\circ$: $\sec 20^\circ=\frac{10}{x}=\frac{10}{9.4}=1.06$ We calculate $\csc 20^\circ$: $\csc 20^\circ=\frac{10}{y}=\frac{10}{3.4}=2.92$
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