Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - 5.5 - Exponential and Logarithmic Models - 5.5 Exercises - Page 405: 24


$ 0.412$

Work Step by Step

We need to use an exponential decay model such as: $y= q( \dfrac{1}{2})^{t/24100}$ or, $q=\dfrac{y}{( \dfrac{1}{2})^{t/24100}} $ or, $q= y \times ( \dfrac{1}{2})^{-t/24100}$ The initial quantity after $1000$ years is: $q= 0.4 \times ( \dfrac{1}{2})^{-1000/24100} \approx 0.412$
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