## Algebra and Trigonometry 10th Edition

$303580.52$
We have $A=P(1+\dfrac{r}{n})^{nt}$ Re-write as: $P=A(1+\dfrac{r}{n})^{-nt}$ Plug in the given values: $P=500000(1+\dfrac{0.05}{12})^{-(12)(10)} \approx 303580.52$