## Algebra and Trigonometry 10th Edition

$296003.78$
We have $A=P(1+\dfrac{r}{n})^{nt}$ Re-write as: $P=A(1+\dfrac{r}{n})^{-nt}$ Plug in the given data: $P=500000(1+\dfrac{0.035}{12})^{-(12)(15)} \approx 296003.78$