## Algebra and Trigonometry 10th Edition

False. $\sqrt {f(x)}\ne\frac{1}{2}f(x)$
Use the Power Property: $\frac{1}{2}f(x)=\frac{1}{2}\ln x=\ln x^{\frac{1}{2}}=\ln\sqrt x=f(\sqrt x)\ne\sqrt {f(x)}=\sqrt {\ln x}$