Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - 5.3 - Properties of Logarithms - 5.3 Exercises - Page 387: 103

Answer

Using a graphing utility, the graphs of the functions $y_1$ and $y_2$ are as shown. No. From the domain of $y_1$ which is $x\gt3$ and from the domain of $y_2$ which is $x\gt0\text{ or }x\gt 3$, some numbers are in the domain of one function but not the other.

Work Step by Step

Using a graphing utility, the graphs of the functions $y_1$ and $y_2$ are as shown. No. The graphs do not show the functions with the same domain. Finding the domain of $y_1$: From $\ln x$: $$x\gt0$$ From $\ln (x-3)$: $$x-3\gt0$$ $$x\gt3$$ Combining: $$x\gt0\text{ and }x\gt3$$ $$x\gt3$$ Thus, the domain for $y_1$ is $x\gt3$. Finding the domain of $y_2$: $$\frac{x}{x-3}\gt0$$ Finding the intervals: $$x=0$$ $$x-3=0$$ $$x=3$$ Then, the intervals are: $$x\lt0,~0\lt x\lt3,~x\gt3$$ Checking for valid solutions: For $x=-1$: $$\frac{-1}{-1-3}\gt0$$ $$\frac{1}{4}\gt0~True$$ Thus, $x\lt0$ is an interval for the domain. At $x=1$: $$\frac{1}{1-3}\gt0$$ $$-\frac{1}{2}\gt0~False$$ Thus, $0\lt x\lt 3$ is not an interval for the domain. At $x=4$: $$\frac{4}{4-3}\gt0$$ $$4\gt0~True$$ Thus, $x\ge3$ is an interval for the domain. Thus, combining the valid intervals which is the domain for $y_2$: $$x\lt0\text{ or }x\gt 3$$ Therefore, from the domain of $y_1$ which is $x\gt3$ and from the domain of $y_2$ which is $x\lt0\text{ or }x\gt 3$, some numbers are in the domain of one function but not the other.
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