Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - 5.3 - Properties of Logarithms - 5.3 Exercises - Page 387: 101

Answer

The Power Property was misused.

Work Step by Step

Incorrect use of the Power Property: $\ln e^2=2\ln e=2(1)=2$ But we should have: $(\ln e)^2=1^2=1$ since the entire expression is raised to the second power.
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