Algebra and Trigonometry 10th Edition

$x_1=3$ and $x_2=-2$
$\ln(x^2-x)=\ln6$ $x^2-x=6~~$ (One-to-One Property) $x^2-x-6=0~~$ ($a=1,~~b=-1,~~c=-6)$ $x=\frac{-(-1)±\sqrt {(-1)^2-4(1)(-6)}}{2(1)}=\frac{1±\sqrt {25}}{2}=\frac{1±5}{2}$ $x_1=\frac{6}{2}=3$ and $x_2=\frac{-4}{2}=-2$