Algebra and Trigonometry 10th Edition

$\ln\frac{1}{e^2}=-2$
$\frac{1}{e^2}=(\frac{1}{e})^2=e^{-2}$ $\ln\frac{1}{e^2}=\ln e^{-2}~~$ (Use the Inverse Property, page 375: $e^{\ln x}=x$): $\ln\frac{1}{e^2}=-2$